Rx = F1x + F2x = 86.60 + 75 = 161.60 N Ry = F1y + F2y = 50 + 129.90 = 179.90 N

Calculate the position vector from O to A.

R = √(Rx^2 + Ry^2) = √(161.60^2 + 179.90^2) = 243.30 N θ = tan^(-1)(Ry/Rx) = tan^(-1)(179.90/161.60) = 48.19°

Calculate the moment of the force about point O.

MO = rOA × F = |i j k| |2 3 4| |Fx Fy Fz|

by Ferdinand P. Beer, E. Russell Johnston Jr., David F. Mazurek, and Michael E. Plesha is a widely used textbook in engineering mechanics courses. Here's a deep dive into the solutions of this book:

vector mechanics for engineers statics 12th edition solutions
vector mechanics for engineers statics 12th edition solutions