Original resistance: [ R = \rho \frac{L}{A} = 20 \ \Omega ]
If the new length ( L' = 3L ) (three times original length), then to keep volume constant, the new area ( A' ) must satisfy: ncert solutions
[ A \times L = A' \times L' ] [ A \times L = A' \times (3L) ] [ A' = \frac{A}{3} ] Original resistance: [ R = \rho \frac{L}{A} =
