Class 10 Electricity Ncert Solutions Instant

Answer: ( H = I^2 R t = 5^2 \times 20 \times 30 = 25 \times 20 \times 30 = 15000 , \text{J} ) In-Text Questions (Page 220) Q1. What determines the rate at which energy is delivered by a current? Answer: Electric power ( P = V \times I = I^2 R = V^2 / R )

Answer: (i) 9 Ω = two in parallel (3 Ω) + one in series (6 Ω) (ii) 4 Ω = two in series (12 Ω) in parallel with one (6 Ω): ( 1/R = 1/12 + 1/6 = 3/12 ) → R=4 Ω class 10 electricity ncert solutions

(a) I²R (b) IR² (c) VI (d) V²/R Answer: (b) IR² Answer: ( H = I^2 R t =

Answer: ( R = V/I = 12 / (2.5 \times 10^{-3}) = 4800 , \Omega ) class 10 electricity ncert solutions

Here are the (based on the latest NCERT textbook).